负指数幂的运算

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负指数幂的运算

2a1b(ab)1 111-2-22-2-3-2-233-3-3-3-1-3-3-23

=2·a·（b）·（c）÷（a）·b =2·（a）·（b）x·(y) =(a·-2+·b)·

baab

1-2-46b1194-3-6 a-63

=2a·b·c÷（ab） =3a·b·x·y=(-2+)·

baab22

(1)（2abc）÷（ab） （2）2a3b1xy2

2-3

-2

-2

3



3

(3)ab



1



a22abb211-2-（-6）-4-36 1911

=a·b·c=a·· =(-+)·

4=14a4b-7c6 =14a4·16 b

7·c=a4c64b7 =（4）(x-1

+y-1

)(x-1

-y-1

) (5)(x=(

1x+111y)(x-y) =(=(121x)-(y)2 =11x2-y2 = = = =(7)(a-1

+b-1)2

-(a-1

-b-1)2

=(

1a+1b)2-(112 a-b)=(1a+121122b2+ab)-(a2+b2-ab) ==112112a2+b2+ab-a2-b

2+ab ==

4ab =





8x

3y6a9=8x3y

6 =-1

+y-1

)÷(x-1

-y-1

) (6)(x1x+1y)÷(1x-1y) =(=(yxy+xxy)÷(yxy-xxy) =(yxyxxy÷xy =yxxyxy·y-x =yx

y-x

=(8) (a-3)2(ab2)-3 =a-6·a-3·b-6 11a·16a3·b6 =1a6•a3•b6

=1

a9b

6 =ababababa22abb2

1ab·ab

ab2

=1ab·ab ab

ab

-2

+y-2

)÷(x-1

-y-1

) 11x

+11

2y2)÷(x-y)

y2x2

yxx2y2+x2y2)÷(xy-xy)

y2x2

yxx2y2

÷xy

y2x2

xyx2y2

·y-x x2y2xy y-x

x2y2

xy2 x2

y

（9）(2mn2)-2(m-2n-1)-3



=2-2·m-4·(m-2)-3·(n-1)-3

116322·m

4·m·n 1m634·m4·n 1234mn




2-3-2-5

（10）(2mn)(mn) （12）(ab)1.(2a)3.(2a2b1)2

-3-32-3-5-2-5 -1-133-22-2-1-2

=2·m·(m)·m·(n)=a·b·(-2)·a·(-2)·(a)·(b)

11111-6-56 3-42

·3·m·m·n =··(-8)·a··a·b 2

(-2)ab8m

11111116 132

=·3·6·5·n=··(-8)·a··4·b

ab8m4amm

=

n62b

= =

8m365 =n6

8m

14

(13)12p1q358p2q4

 (14)1

=2p1·q35p2·q4 =(8

=45pq = = = = =a23

3a2b2c322xy1 2

3a2b2c32x2y1

)-6 (3a2b2c3)6

(2x2y1)

6

36a12b12c1826x12y6



136•1a12

•b12•c181 26•1

x12•y61729•1

a12•b12•c1811



64•x

12•y664b12c18x12

729a12y

6

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